Formulas
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- Predicting
Power
-
- BHP = PLAN/33,000
- P is brake mean effective pressure, in
PSI
- L is piston stroke, in feet
- A is the area of one piston, in square
inches
- N is the number of power strokes per
minute
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- Piston Speed
-
- Cm = .166 x L x N
- Cm is mean piston speed, in feet per
minute
- L is stroke, in inches
- N is crankshaft speed, in RPM
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- Brake Mean Effective Pressure
(BMEP)
-
- 2-Stroke BMEP = (HP x 6500)/(L x RPM)
- 4-Stroke BMEP = (HP x 13000)/(L x RPM)
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- L = Displacement in
Liters
-
- i.e., 80 cc = .08 Liters
- 1 ci. = 16.39 cc
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- Piston
Acceleration
-
- Gmax = ((N^2 x L)/2189) x (1 + 1/(2A))
- Gmax is maximum piston acceleration, in feet
per second squared
- N is crankshaft speed, in RPM
- L is stroke, in inches
- A is the ratio of connecting rod length,
between centers, to stroke
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- Piston Stroke
Motion
- S = R cos X + L cos Z
- S = the distance piston wrist pin is from
center of crankshaft
- R = the radius of the crankshaft wrist
pin
- L = the length of the connecting rod
- X = the angle of the wrist pin
- Z = the angle of the connecting rod
- or
- sin X = R/L sin Z
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- Piston Travel vs. Crank
Rotation
-
- d = ((S/2) + L) - (S/2 cos X) - L
sin[cos-1 (S/2L sin X)]
- S = Stroke (mm)
- L = Connecting Rod Length (mm)
- X = Crank Angle Before or After TDC
(deg)
- Note: (L) Rod Length is usually 2 times the
(S) Stroke
- OR
- For Spreadsheets and some Calculators
- HT = (r + c) - (r cos (a)) - SQRT(c^2 - (r
sin (a))^2)
- r = s/2
- dtor = PI/180
- a = d x dtor
- HT = The height of piston
- r = The stroke divided by 2
- c = The rod length
- a = The crank angle in radians
- d = The crank angle in degrees
- dtor = Degrees to Radians
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- Exhaust Systems Tuned
Length
-
- Lt = (Eo x Vs) / N
- Lt is the tuned length, in inches
- Eo is the exhaust-open period, in
degrees
- Vs is wave speed in feet per second (1700
ft/sec at sea level)
- N is crankshaft speed, in RPM
- Length of Curved Pipe
- L = R x .01745 x Z
- L is length
- R is radius of the pipe bend
- Z is the angle of the bend
- Diffuser Proportions
- D2 = SQRT( D1^2 x 6.25 )
- D2 is the diffuser outlet diameter
- D1 is the diffuser inlet diameter
- 6.25 is the outlet/inlet ratio constant
- Baffle Cones
- Lr = Le/2
- Lr is mean point of the reflection inside
the baffle cone
- Le is the length of the baffle cone
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- Port Open Time
-
- T = ( 60/N ) x ( Z/360 ) or T = Z/( N x
6)
- T is time, in seconds
- N is crankshaft speed, in RPM
- Z is port open duration, in degrees
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- Compression
Ratio
-
- CR = ( V1 + V2 ) / V2
- CR is compression ratio
- V1 is cylinder volume at exhaust
closing
- V2 is combustion chamber volume
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- Carburetor Throttle Bore
Diameter
-
- D = K x SQRT( C x N )
- D is throttle bore diameter, in
millimeters
- K is a constant ( approx. 0.65 to 0.9,
derive from existing carburetor bore)
- C is cylinder displacement, in liters
- N is RPM at peak power
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- Crankcase
Volume
-
- Primary compression ratio =
- Case Volume @ TDC / Case Volume at BDC
- or
- CRp = V1 + V2 / V1
- CRp is the primary compression ratio
- V1 is crankcase volume @ BDC
- V2 is piston displacement
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- Resonance
Effects
-
- F = Vs / 2¼ * the square root of A / Vc (L +
1/2 the square root of ¼ A
- Vs is the sonic speed Uusually about 1100
ft/sec)
- A is the cross-sectional area of the
inlet
- L is the inlet pipe length
- Vc is the flask (crankcase) volume
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- Average Exhaust
Temperature
-
- Determine the exhaust gas temperature in
Kelvin
- (k = C + 273.15). This is usually a function
of the engine's BMEP.
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- Torque
-
- 1.00 lb-ft = 0.138 kg-m = 1.35 N-m
- 1.00 kg-m = 7.23 lb-ft. = 9.81 N-m
- 1.00 N-m = 0.102 kg-m = 0.737 lb-ft
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- Mass
-
- 1.00 lb = 0.454 kg = 4.45 N
- 1.00 kg = 2.20 lbs = 9.81 N
- 1.00 N = 0.102 kg = 0.220 lb
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- Distance
-
- 1 in = 2.54 cm = 0.0000158 mi = 0.0000254
km
- 1 cm = 0.394 in = 0.00000621 mi = 0.00001
km
- 1 ft = 30.5 cm = 0.000189 mi = .000305
km
- 1 mi = 63,360 in = 160,934.4 cm = 1.609
km
- 1 km = 0.621 mi = 100,000 cm = 3281 ft
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- Pressure
-
- 1.00 bar = 14.5 psi = 1.02 kg/sq-cm = 100
kPa
- 1.00 psi = 0.069 bar = 0.070 kg/sq-cm = 6.89
kPa
- 1.00 kg/sq-cm = 0.980 bar = 14.2 psi = 98.1
kPa
- 1.00 kPa = 0.010 bar = 0.145 psi = 0.010
kg/sq-cm
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- Temperature
-
- F = 9 / 5 x C + 32
- C = 5/9 (F - 32)
- K = C + 273.4
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- Area / Volume
-
- 1.00 sq-in = 6.452 sq-cm
- 1.00 sq-cm= 0.155 sq-in
- 1.00 cu-in = 16.387 cc
- 1.00 cc = 0.0610 cu-in
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- Power
-
- 1.00 HP = 746 W
- torque (lb-ft) = 5252 x hp / rpm
- hp = rpm x torque (lb-ft) / 5252
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The Weight of Air
- 14.7 lbs. per sq. inch at sea level.
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Air Density Calculation
- StdAirDensity = 1.22556 and is defined at
59.0F degrees, 0.0% humidity, and 29.92 inches
on the barometer.
-
- Temp_c = (Temp-32.0) * 5.0 / 9.0;
- Temp_k = Temp_c + 273.0;
- Baro_mb = Barometer / (29.92 / 1013.0);
- Baro_pa = Baro_mb * 100.0;
- SaturationPressure_mb = 6.11 *
pow(10,(7.5*Temp_c)/(237.7+Temp_c));
- VaporPressure_mb = Humidity *
SaturationPressure_mb / 100.0;
- TempVirtual_k = Temp_k / (1.0 -
(VaporPressure_mb/Baro_mb)*(1.-0.622));
- // D = P/(T*R)
- AirDensity = Baro_pa /
(TempVirtual_k*GasConstant);
- % Std Density =
AirDensity/StdAirDensity*100
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Additional Conversion Factors
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- 1 Centimeter - 0.0328084 foot; 0.393701
inch
-
- 1 Circular Mil - 7.853982 x 10 to the
negative seventh square inches; 5.067075 x 10 to
the negative sixth square centimeters
-
- 1 Cubic Centimeter - 0.061024 cubic inch;
0.270512 dram (U.S. fluid); 16.230664 minims
(U.S.); 0.999972 milliliter
-
- 1 Cubic Foot - 0.803564 bushel (U.S.);
7.480520 gallons (U.S. liquid); 0.028317 cubic
meter; 28.31605 liters
-
- 1 Cubic Inch - 16.387064 cubic
centimeters
-
- 1 Cubic Meter - 35.314667 cubic feet;
264.17205 gallons (U.S. liquid)
-
- 1 Foot - 0.3048 meter
-
- 1 Gallon (U.S. liquid) - 0.1336816 cubic
foot; 0.832675 gallon (British); 231 cubic
inches; 0.0037854 cubic meter; 3.785306
liters
-
- 1 Grain - 0.06479891 gram
-
- 1 Gram - 0.00220462 pound (avoirdupois);
0.035274 ounce (avoirdupois); 15.432358
grains
-
- 1 Hectare- 2.471054 acres; 1.07639 x 10 to
the fifth square feet
-
- 1 Inch - 2.54 centimeters
-
- 1 Kilogram - 2.204623 pounds
(avoirdupois)
-
- 1 Kilometer - 0.621371 mile (statute)
-
- 1 Liter - 0.264179 gallon (U.S.
liquid);0.0353157 cubic foot; 1.056718 quarts
(U.S. liquid)
-
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- 1 Meter - 1.093613 yards; 3.280840 feet;
39.37008 inches
-
- 1 Mile (statute) - 1.609344 kilometers
-
- 1 Ounce (U.S. fluid) - 1.804688 cubic
inches; 29.573730 cubic centimeters
-
- 1 Ounce (avoirdupois) - 28.349523 grams
-
- 1 Ounce (apothecary or troy) - 31.103486
grams
-
- 1 Pint (U.S. liquid) - 0.473163 liter;
473.17647 cubic centimeters
-
- 1 Pound (avoirdupois) - 0.453592 kilogram;
453.59237 grams
-
- 1 Pound (apothecary or troy) - 0.3732417
kilogram, 373.24172 grams
-
- 1 Quart (U.S. dry) - 1.10119 liters
-
- 1 Quart (liquid) - 0.946326 liter
-
- 1 Radian - 57.295779 degrees
-
- 1 Rod - 5.0292 meters
-
- 1 Square Centimeter - 0.155000 square
inch
-
- 1 Square Foot - 0.09290304 square meter
-
- 1 Square Inch - 645.16 square
millimeters
-
- 1 Square Meter - 10.763910 square feet
-
- 1 Square Yard - 0.836127 square meter
-
- 1 Ton (short) - 907.18474 kilograms
-
- 1 Yard - 0.9144 meter
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POWER - AC CIRCUITS
- Efficiency = 746 x Output HP / Input
Watts
- 3ø KW = Volts x Amps x PF x 1.732 /
1000
- 3ø Amps = 746 x HP / 1.732 x Eff. x
PF
- 3ø Eff. = 746 x HP / 1.732 x Volts x
Amps x PF
- 3ø PF = Input Watts / Volts x Amps x
1.732
- 1ø KW = Volts x Amps x PF / 1000
- 1ø Amps = 746 x HP / Volts x Eff. x
PF
- 1ø Eff. = 746 x HP / Volts x Amps x
PF
- 1ø PF = Input Watts / Volts x
Amps
- HP (3ø) = Volts x Amps x 1.732 x Eff.
x PF / 746
- HP (1ø) = Volts x Amps x Eff. x PF /
746
- 1 KW = 1000 Watts
-
- Eff. = Efficiency, PF = Power Factor, KW =
Kilowatts, HP = Horsepower
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- POWER - DC
CIRCUITS
-
- Torque = HP x 5280 /
RPM
- HP = Torque X RPM /
5280
- 1 HP = 36 lb.in. @ 1750
RPM
- 1 HP = 3 lb. ft. @ 1750
RPM
-
Eff. = Efficiency, HP = Horsepower
OHMS LAW
-
- Volts (E) = Amps (I) x Ohms
(R)
- Amps (I) = Volts (E) / Ohms
(R)
- Ohms (R) = Volts (E) / Amps
(I)
-
R=Ohms, E=Volts, I=Amperes
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- To figure miles per hour, multiply the
engine RPM by the Wheel Diameter in inches and
divide this by the Gear Ratio times 336
- or
- MPH = RPM * wheel diameter (in inches) /
gear ratio * 336
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To figure engine speed (RPM), multiply by the
Speed in MPH, by the rear axle gear ratio times
336. Divide this by the tire diameter in
inches.
or
RPM = MPH * gear ratio * 336 / tire diameter
Minimum engine horsepower required to reach a 1/4 mile speed:
HPq = (0.00426 x MPH) x (0.00426 x MPH) x (0.00426 x MPH) x WEIGHT
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Main 33
Coupe Page
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